Erratum: “Dynamic Modeling and Experimental Validation of Eddy Current Dampers and Couplers” [Journal of Vibration and Acoustics, 2008, 130, pp. 021011-1–021011-9]

Notes

1
The corrections are all linked to the quantity Ω that is absent in several equations within the paper.
2
The corrections are summarize below.

Table 1

Page	Line equation	Original	Correction
021011-4	Line 291 Eq. (10)	$φ_{r} = φ_{r 0} e^{- jpt} φ_{r 0} = \frac{j φ_{rs 0}}{ω_{p} - jp}$	$φ_{r} = φ_{r 0} e^{- jp Ω t}; φ_{r 0} = \frac{j Ω φ_{rs 0}}{ω_{p} - jp Ω}$
021011-4	Line 295 Eq. (11)	$T (Ω) = \frac{c_{0}}{1 + {(p)}^{2} / ω_{p}^{2}}$	$T (Ω) = \frac{c_{0}}{1 + {(p Ω)}^{2} / ω_{p}^{2}} Ω$
021011-4	Line 300	$(p ≪ ω_{p})$	$(p Ω ≪ ω_{p})$
021011-4	Line 305	$T = c_{0}$	$T = c_{0} Ω$
021011-4	Line 306	$p >> ω_{p}$	$p Ω >> ω_{p}$
021011-5	Line 354 Eq. (18)	$T_{\max} = \frac{ω_{p}}{p} T_{\max} = \frac{c_{em} ω_{p}}{2 p} = \frac{k_{em}}{2 p}$	$Ω_{T_{\max}} = \frac{ω_{p}}{p}, T_{\max} = \frac{c_{em} ω_{p}}{2 p} = \frac{k_{em}}{2 p}$
021011-6	Line 463	$T = c_{0} (Eq . (12))$	$T = c_{0} Ω (Eq . (12))$
021011-6	Line 500 Eq. (21)	$T_{\max} = \frac{c_{0} ω_{p}}{2 p} = 49.8 Nm, T_{\max} = \frac{ω_{p}}{p} = 766 rpm$	$T_{\max} = \frac{c_{0} ω_{p}}{2 p} = 49.8 Nm, {Ω_{T}}_{_{\max}} = \frac{ω_{p}}{p} = 766 rpm$

Page	Line equation	Original	Correction
021011-4	Line 291 Eq. (10)	$φ_{r} = φ_{r 0} e^{- jpt} φ_{r 0} = \frac{j φ_{rs 0}}{ω_{p} - jp}$	$φ_{r} = φ_{r 0} e^{- jp Ω t}; φ_{r 0} = \frac{j Ω φ_{rs 0}}{ω_{p} - jp Ω}$
021011-4	Line 295 Eq. (11)	$T (Ω) = \frac{c_{0}}{1 + {(p)}^{2} / ω_{p}^{2}}$	$T (Ω) = \frac{c_{0}}{1 + {(p Ω)}^{2} / ω_{p}^{2}} Ω$
021011-4	Line 300	$(p ≪ ω_{p})$	$(p Ω ≪ ω_{p})$
021011-4	Line 305	$T = c_{0}$	$T = c_{0} Ω$
021011-4	Line 306	$p >> ω_{p}$	$p Ω >> ω_{p}$
021011-5	Line 354 Eq. (18)	$T_{\max} = \frac{ω_{p}}{p} T_{\max} = \frac{c_{em} ω_{p}}{2 p} = \frac{k_{em}}{2 p}$	$Ω_{T_{\max}} = \frac{ω_{p}}{p}, T_{\max} = \frac{c_{em} ω_{p}}{2 p} = \frac{k_{em}}{2 p}$
021011-6	Line 463	$T = c_{0} (Eq . (12))$	$T = c_{0} Ω (Eq . (12))$
021011-6	Line 500 Eq. (21)	$T_{\max} = \frac{c_{0} ω_{p}}{2 p} = 49.8 Nm, T_{\max} = \frac{ω_{p}}{p} = 766 rpm$	$T_{\max} = \frac{c_{0} ω_{p}}{2 p} = 49.8 Nm, {Ω_{T}}_{_{\max}} = \frac{ω_{p}}{p} = 766 rpm$

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by American Society of Mechanical Engineers